Question

one of the two digit of a two digit number is twice the other digit.if you interchange the digit of two digit number and add the resulting number to the original number , you get 66 . what is the original number.​

Answer 1

Answer:

hope you got the answer

Answer 2

$\sf\red{ QUESTION : - }$

one of the two digit of a two digit number is twice the other digit.if you interchange the digit of two digit number and add the resulting number to the original number , you get 66 . what is the original number.

$\sf\green{ ANSWER : - }$

$\sf\orange{ Case 1 : - }$

When the digit in the units place is twice the digit in the tens place

Let the digit in the units place be x .

then , the digit in the units place = 2x

and the two-digit number = 10 × x + 2x = 12x

No. with interchanged digits = 10 × 2x + x = 21x

Number + Number with interchanged digits= 66

→ 12x + 21x = 66

→ 33x = 66

→ x = 66/33 = 2

Original number = 12x = 12 x 2 = 24

$\sf\orange{ Case 2 : - }$

When the digit in the tens place is twice the digit in the units place .

Let the digit in the units place be x .

then , the digit in the tens place = 2x

and the two-digit number = 10 × 2x + x = 21x

No. with interchanged digits = 10 × x + 2x = 12x

Number + Number with interchanged digits= 66

→ 21x + 12x = 66

→ 33x = 66

→ x = 66/33 = 2

Original number = 12x = 21 x 2 = 42

Hence , the original number is 24 or 42.