One of the two digits of a two digit number is three time the other digit.If you enterchange the digit of this two digit number and add the resulting number to the original number ,you get88.What is the original number
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≡QUESTION≡
One of the two digits of a two digit number is three time the other digit.If you interchange the digit of this two digit number and add the resulting number to the original number ,you get 88. What is the original number?
║⊕ANSWER⊕║
Let us assume that the units place of a two digit number is x.
Then as per the question, tenth place of the number is 3x.
Thus, the two digit number is 10(3x) + x.
If we interchange the digits the number becomes : 10x + 3x
10(3x) + x + 10x + 3x = 88
30x + 14x = 88
44x = 88
x = 2
Hence the two digit number is 10(6) + 2 = 62
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