Question

One Of the two digits of a two digit number is three times the other digit if they interchange the digit of this two digit number and at the resulting to the original number you get 88 what is the original number?​

Answer 1

Answer:

Let the digit in units place = x

The digit in tens place = 3x

The number is 10(3x) + x = 31x

Digits are interchanged

Digit in units place = 3x

Digit in tens place = x

The new number= 10(x) + 3x = 13x

Sum of these two numbers = 88

31x + 13x = 88

44x = 88

x = 2

3x = 6

The original number is 62

hope it helps you

Answer 2

HEY MATE! :)

here your answer......

Let the unit digit = x

and tens digit = 3x

Number = x+30x = 31x

A/Q,

aftrer interchanging the digits,

Number = 3x+10x = 13x

 New Number = Number + Original Number = 88 

New Number = 13x+ 31x = 88

or,   44x = 88

or,        x = 88/44 = 2

Hence the Original Number = 31x = 31*2 = 62

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