Question

One of the two digits of a two digit number is three times the other digit. If you
interchange the digits of this two-digit number and add the resulting number to the
original number, you get 88. What is the original number?​

Answer 1

Answer:

X= 2 and Y= 6 or vice verca

Step-by-step explanation:

You explanation is in the pic attached pkease mark me as brainliest

Answer 2

AnsWer :

62.

To FinD :

The Original number.

SolutioN :

Let,

• The unit place digit be x.
• Then, tenth place digit is 3x.

$\rule{90}2$

Case 1.

Taking Original number.

$\tt : \implies10 \times (3x) + 1(x)$

$\tt : \implies30x + x.$

$\tt : \implies31x.$

$\rule{90}2$

Case 2.

Taking Reversing number.

$\tt : \implies 10\times(x) + 1(3x)$

$\tt : \implies 10x + 3x$

$\tt : \implies 13x.$

• If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88.

$\tt : \implies 13x + 31x = 88$

$\tt : \implies \cancel{44}x = \cancel{88}$

$\tt : \implies x = 2.$

$\rule{120}2$

Now, Let's Find the Original number.

$\tt : \implies 31x.$

$\tt : \implies 31(2).$

$\tt : \implies 62.$

Therefore, the value of the Original number is 62.