Question

One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

Answer 1

Let the digits be x and 3x

One's digit =x

Ten digit=10(3x)

=30x

=x+30x

Original number=31x

Interchange the digits

One's digit=3x

Ten's digit=10(x)

=10x

=3x+10x

New number=13x

31x+13x=88

44x=88

$x = \frac{88}{44}$

x=2

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One's digit=2

Ten's digit=2(3)=6

Thus, The number is 26 or 62

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