Question

One of the two digits of a two digit number is three times the other

digit. If you interchange the digits of this two-digit number and add the

resulting number to the original number, you get 88. What are the two

numbers?

Answer 1

Answer:

Let the digit in units place be x.

Then, digit in ten's place =3x

So, original number =10(3x)+x=31x

On interchanging the digits, new number =10x+3x=13x

According to the given condition,

31x+13x=88

⇒44x=88

⇒x=2

So, the original number is 31x or 31×2=62.

On the other hand, if we consider the digit in ten's place as x, then the digit in unit's place will be 3x.

So, the resulting number we get is 26.

Here, both answers are correct, as 26+62=88.

Answer 2

$\huge\Large\underline\mathtt\pink{Step-by-step explanation:-}$

$\huge\Large\underline\mathtt\pink{Given :-}$

One of the two digits of a two digit number is three times the other digit.

If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88.

$\huge\Large\underline\mathtt\pink{Find :-}$

The Number

$\huge\Large\underline\mathtt\pink{Solution:-}$

Let the digits at tens place be x.

And ones place be 3x .

Original Number = 10x + 3x = 13x

Number after interchanging = 10 × 3x + x = 30x + x = 31x

$\huge\Large\underline\mathtt\pink{According to the Question,:-}$

⇒ Original number + New number = 88

⇒ 13x + 31x = 88

⇒ 44x = 88

⇒ x = 88/44

⇒ x = 2

Original Number = 13x = 13 × 2 = 26

Therefore, by considering the tens place and ones place as 3x and x.

Therefore, by considering the tens place and ones place as 3x and x.The two digit number obtained is 62.

Therefore, by considering the tens place and ones place as 3x and x.The two digit number obtained is 62.Hence, the two-digit number may be 26 or 62.

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