Question

One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

Answer 1

Let the unit digit = x

and tens digit = 3x

Number = x+30x = 31x

A/Q,

aftrer interchanging the digits,

Number = 3x+10x = 13x

 New Number = Number + Original Number = 88 

New Number = 13x+ 31x = 88

or,   44x = 88

or,        x = 88/44 = 2

Hence the Original Number = 31x = 31*2 = 62

Answer 2

$\huge\sf\pink{Answer}$

☞ Original number = 62

$\rule{110}1$

$\huge\sf\blue{Given}$

➝ In a 2 digit number a number is three times the other number

➝ If we interchange the digits of the 2 digit number and add the resulting number to the original one we get 88

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

✭ The original number?

$\rule{110}1$

$\huge\sf\purple{Steps}$

$\bullet\:\sf\ Let \: the \: one's \: place \: digit \: be \: \bf\ x$

$\bullet\:\sf\ So, \: ten's \: place \: digit \: number \: is \: \bf\ 3x$

$\normalsize\underline{\boxed{\sf{Original \: number = 10 \times\ Ten's \: place \: digit + one's \: place \: digit }}}$

$\normalsize\twoheadrightarrow\sf\ Original_{no.} = 10 \times\ 3x + x \\ \\\normalsize\twoheadrightarrow\sf\red\ Original_{no.} = 31x$

$\normalsize\underline{\boxed{\sf{Reversing \: number = 10 \times\ One's \: place \: digit + ten's \: place \: digit }}}$

$\normalsize\twoheadrightarrow\sf\ Reversing _{no.} = 10 \times\ x + 3x \\ \\ </p><p>\normalsize\twoheadrightarrow\sf\green\ Reversing_{no.} = 13x$

$\underline{\dag\:\textsf{According \: to \: the \: question \: now:}}$

$\normalsize\dashrightarrow\sf\ Original_{no.} + Reversing_{no.} = 88$

$\normalsize\dashrightarrow\sf\ 31x + 13 x = 88$

$\normalsize\dashrightarrow\sf\ 44x = 88$

$\normalsize\dashrightarrow\sf\ x = \frac{\cancel{88}}{\cancel{44}}$

$\normalsize\dashrightarrow\sf\ x = 2$

$\normalsize\dashrightarrow\sf\ Original_{no.} = 31x$

$\normalsize\dashrightarrow\sf\ Original_{no.} = 31 \times\ 2$

$\normalsize\orange{\dashrightarrow\sf\ Original_{no.} = 62}$

$\rule{170}3$