Question

One.of the two digits of a two digit number is twice the other digit.if you interchange the digit of the two digit number and add the.resulting number to the original number you get 66,what is the original number

Answer 1

=10(2x)+x=20x+x=21x
=10(x)+2x=10x+2x=12x
after interchanging
21x+12x=66
33x=66
x=66/33
x=3

Answer 2

Answer:

42

Step-by-step explanation:

Let one of two digit number be x

Since we are given that One.of the two digits of a two digit number is twice the other digit

So, other digit = 2x

So, Number = $10(2x)+x$

Now if you interchange the digit of the two digit number

Interchanged Number = $10(x)+2x$

Add the resulting number to the original number you get 66

$10(2x)+x+10(x)+2x =66$

$20x+x+10x+2x =66$

$33x =66$

$x =\frac{66}{33}$

$x =2$

So, The original number =  $10(2x)+x = 10(2 \times 2)+2 =42$

Hence the number is 42