One of the two equal angles of an isosceles triangle measure 65° .find the measure of each angle of the triangle .
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Angle 1 = 65°
Angle 2 = 65° {equal angle of an isosceles triangle}
Let angle 3 = X
Sum of all angle in a triangle = 180°
65 + 65 + X = 180°
130 + X = 180°
X = 180 - 130
X = 50°
Therefore angles of triangle are = 65°, 65° and 50°.
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Angle 2 = 65° {equal angle of an isosceles triangle}
Let angle 3 = X
Sum of all angle in a triangle = 180°
65 + 65 + X = 180°
130 + X = 180°
X = 180 - 130
X = 50°
Therefore angles of triangle are = 65°, 65° and 50°.
Hope it helps.
If you satisfied mark it brainliest.
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Given - In an Isosceles triangle one of the equal Angle = 65°
To find - All angles of the isosceles triangle.
Calculation - Angle 2 = Angle 1 = 65°
As it's an isosceles triangle, the angles of the equal sides would be equal.
Let third angle be x
Thus, x + 65 + 65 = 180°
By the Angle sum property of a triangle.
Thus, x + 130 = 180
x = 180 - 130
x = 50°
Thus, the second angle = first angle = 65° and the third angle = 50°
Hope it helps !
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