one of the two identical slits in ydse is covered with glass so that light intensity is reduced to 50% ,find the ratio if maximum and minimum intensity of fringes in interference pattern
Pjpndm:
Class 12?
yeah i have
Take I(max)=[a+a/2]^2 and I(min)=[a-a/2]^2
Answer is 9:1
Am I right
yeah sorry I need points so i answered that
Answers
Answered by
6
I already answered this question ,
Answer is in such a way -----
Let initial intensity of light passing through each slit is I₀ .
According to question,
one of two slits is covered with glass as shown in figure ,such that the intensity of light passing through it is reduced to 50% .
Means intensity of this slit will be I₀/2 after covering with glass .
Now, use formula
answer is (√2+1)² : (√2-1)²
Read more on Brainly.in - https://brainly.in/question/2839841#readmore
Answer is in such a way -----
Let initial intensity of light passing through each slit is I₀ .
According to question,
one of two slits is covered with glass as shown in figure ,such that the intensity of light passing through it is reduced to 50% .
Means intensity of this slit will be I₀/2 after covering with glass .
Now, use formula
answer is (√2+1)² : (√2-1)²
Read more on Brainly.in - https://brainly.in/question/2839841#readmore
Similar questions