Question

One of the two numbers of a two digit number is 4 times the other digit. If we interchange the digits and add the resulting number to the original number we get 110.What is the original number​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Let the number at tens place be x and units place be y.

Therefore, the required number is :

10x+y

From first condition,

x=4y

From second condition,

10x+y+10y+x=110

11x+11y=110

x+y=10............ (2)

4y+y=10.........From (1)

5y=10

y=10/5

y=2

Substituting the value of y in (1)

x=4y

x=4×2

x=8

Therefore,

The original number:

10x+y=10×8+2

=82