Physics, asked by lohithasrilakshmi, 1 day ago

One of the two particles moving with constant velocity of 50m/s and the other start form rest & moving with uniform acceleration of 10m/s. They start moving simultaneously from the same position in the same direction. When they will be separated by a distance of 125m from each other?​

Answers

Answered by raghav22589
0

Answer:

u  

1

=50m/s

u  

2

=0

s  

1

=u×t

a  

2

=10m/s  

2

 

s  

1

=50t

s  

2

=u  

2

t+  

2

1

a  

2

t  

2

 

s  

2

=0+  

2

1

×10×t  

2

=5t  

2

 

s  

1

−s  

2

=125⇒50t−5t  

2

=125

⇒t  

2

−10t+25=0⇒t=5

Explanation:

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