One of the two particles moving with constant velocity of 50m/s and the other start form rest & moving with uniform acceleration of 10m/s. They start moving simultaneously from the same position in the same direction. When they will be separated by a distance of 125m from each other?
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Answer:
u
1
=50m/s
u
2
=0
s
1
=u×t
a
2
=10m/s
2
s
1
=50t
s
2
=u
2
t+
2
1
a
2
t
2
s
2
=0+
2
1
×10×t
2
=5t
2
s
1
−s
2
=125⇒50t−5t
2
=125
⇒t
2
−10t+25=0⇒t=5
Explanation:
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