Question

one of the two rectangular components of a force is 20N and it makes an angle of 30degrees with the force. find th magnitude of the other component.

Answer 1

May be this is correct answer

Answer 2

Answer:

The magnitude of the other component is $\dfrac{20}{\sqrt{3}}\ N$.

Explanation:

Given that,

Force $F_{1} = 20\ N$

Angle = 30°

We know the two rectangular components are perpendicular to each other.

So, given the angle made by one of the component with its original vector is 30°.

The magnitude of the one component is

$F_{1}=F \cos30^{\circ}= 20 N$

$F=\dfrac{20\times2}{\sqrt{3}}$

$F=\dfrac{40}{\sqrt{3}}$

$F=23.09\ N$

The magnitude of the other component is

$F_{2}=F \sin30^{\circ}$

$F_{2}=\dfrac{40}{\sqrt{3}}\times\dfrac{1}{2}$

$F_{2}=\dfrac{20}{\sqrt{3}}\ N$

Hence, The magnitude of the other component is $\dfrac{20}{\sqrt{3}}\ N$.