Question

One of the zeroes of the polynomial 2x²+ 7x – 4 is
(a) 2
(b) 1/2
(c) 4
(d) -2 ​

Answer 1

p(x) = 2x² + 7x - 4

==> 2x² + 8x - x - 4 = 0

==> 2x(x + 4) - 1(x + 4) = 0

==> (x + 4)(2x - 1) = 0

∴ x = -4, 1/2

Hence, Option (b) is correct.

Answer 2

Answer:

$2 {x}^{2} + 7x - 4 = 0\\ 2 {x}^{2} + 8x - x - 1 = 0\\ 2x(x + 4) - 1(x + 4) \\ (x + 4)(2x - 1) = 0 \\ x = - 4 \: and \: \frac{1}{2} \\ so \: option \: (b) \: is \: the \: right \: ans$

Hope its help uh❤✌