Question

one of the zeros of the polynomial 2x square + 7 x minus 4​

Answer 1

Answer:

Hi buddy this will be your answer.

p(x)=2x^(2)+7x-4

p(0)=2(0)^(2)+7 (0)-4

p(0)=0+0-4

p (0)=-4

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answer

Answer 2

Question:

One of the zeroes of the polynomial  2x² + 7x - 4​ = 0  is 1/2. Find the other zero.

Solution:

Since 1/2 is a zero of  2x² + 7x - 4 = 0,  then  (x - 1/2) can be a factor.

To get it easier, since the coefficient of x² is 2 and 1/2 is a zero, we change the factor  (x - 1/2)  as  (2x - 1).  This makes the coefficient of x of the other factor, 1.

Let that factor be  (x - a),  where  a  is the other zero of the polynomial.  We have to find the value of  a.

Now,

(2x - 1)(x - a) = 2x² + 7x - 4

2x² - 2ax - x + a = 2x² + 7x - 4

2x² - (2a + 1)x + a = 2x² + 7x - 4

From here, taking the constant term from both sides. we get,

a = - 4

Hence,  - 4  is the answer.