Math, asked by 47237, 6 months ago

One order of fries cost is placed for 6 order of fries, what will the total cost of the order be.

Answers

Answered by paswanomkar7897
0

Answer:

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Step-by-step explanation:

The Crawford and Smith families ordered lunch at the football game. The Crawford family ordered 4 hot dogs, 3 veggie burgers, and 7 orders of french fries, and paid $36. The Smith family ordered 6 hot dogs, 2 veggie burgers, and 8 orders of french fries, and paid $39.

Answered by Meetkoshiya
0
Let h = hotdogs
v = veggie burger
f = french fries


4h + 3v + 7f = $36
6h + 2v + 8f = $39

We know that an order of french fries costs $1.75

4h + 3v + 7(1.75) = $36 -----> 4h + 3v + 12.25 = 36 -----> 4h + 3v = 36 - 12.25
6h + 2v + 8(1.75) = $39 -----> 6h + 2v + 14 = 39 -----> 6h + 2v = 39 - 14



4h + 3v = 23.75 Equation (1)
6h + 2v = 25 Equation (2)

Eliminate v by multiplying eq. 1 by -2 and eq. 2 by 3

(4h + 3v = 23.75) (-2) -------> -8h - 6v = -47.50
(6h + 2v = 25) (3) -------> 18h + 6v = 75
_____________________
Find the sum. 10h + 0 = 27.50

10h = 27.50

10h/10 = 27.50/10

h = $2.75

Solve for v:

6h + 2v = 25


6 (2.75) + 2v = 25

16.50 + 2v = 25

2v = 25 - 16.50

2v = 8.50

2v/2 = 8.50/2

v= $4.25

Now add the cost of a hotdog and the cost of a veggie burger.

h + v =

$2.75 + $4.25 = $7

Hope that helps.
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