one person bought some kg sugar in rs 80.if you would get4kg more sugar with that money then the price of 1 kg
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Let the price of the sugar per kg = x
Weight of sugar bought for Rs 56 = 56 x kg
Reduced price of the sugar = (x - 1)
Weight of the sugar bought for Rs 56 = 56 (x - 1) kg
⇒ 56 (x - 1) - 56 x = 1
⇒ 56 [1 (x - 1) - 1 x] = 1
⇒ 56 [x-x+1 (x2-x) ] = 1
⇒ x2 - x - 56 = 0
⇒ (x - 8)(x + 7) = 0
⇒ x = 8 or -7
The price of an object cannot be negative.
So, the original price of the sugar per kg = Rs 8
Plz mark it as brainlist
Let the price of the sugar per kg = x
Weight of sugar bought for Rs 56 = 56 x kg
Reduced price of the sugar = (x - 1)
Weight of the sugar bought for Rs 56 = 56 (x - 1) kg
⇒ 56 (x - 1) - 56 x = 1
⇒ 56 [1 (x - 1) - 1 x] = 1
⇒ 56 [x-x+1 (x2-x) ] = 1
⇒ x2 - x - 56 = 0
⇒ (x - 8)(x + 7) = 0
⇒ x = 8 or -7
The price of an object cannot be negative.
So, the original price of the sugar per kg = Rs 8
Plz mark it as brainlist
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