Question

one person goings to 20km North 10km east who the person is displacement.
questions the answer is 22.33km.
can solve the formula.​

Answer 1

Answer:

Let the body go along OA = 20 km towards north and OB = 10 km towards east. Then the displacement of the body is given by the hypotenuse AB of the triangle OAB.

(ab)2=(ob)2+(oa) 2

(ab) 2= (10)2+(20)2= 10x10 +20x20

=100+ 400

(ab) 2=500

ab=√500

ab =23.3606