one plus sin squared theta equal to 3 sin theta cos theta
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look out above please...i have given the answer in the form of general solution of trigonometry
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TO FIND
the general equation of 1 + sin^2θ = 3sinθcosθ
GIVEN
1 + sin^2θ = 3sinθcosθ
SOLUTION
1 + sin^2θ = 3sinθcosθ
cos^2θ + sin^2θ + sin^2θ = 3sinθcosθ
cos^2θ+2sin^2θ-3sinθcosθ=0
2sin^2θ - 2sinθcosθ - sinθcosθ + cos^2θ = 0
2sinθ(sinθ-cosθ)-cosθ(sionθ-cosθ)=0
(2sinθ-cosθ)(sinθ-cosθ)=0
ANSWER
now equating with zero
sinθ-cosθ=0
tanθ=1
θ=nπ+π/4
n∈I
2sinθ-cosθ=0
tanθ=1/2
θ=nπ+α
α=tan^-1(1/2)
n∈I
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