one plus y squared DX equals to X + y cube + y d y
Attachments:
Answers
Answered by
1
(1+y^2)dx = (x + y^3 +y)dy
dx/dy = (x + y^3 +y)/(1+y^2)
dx/dy = x/(1+y^2) + (y^3 +y)/(1+y^2)
dx/dy = x/(1+y^2) + y
dx/dy -x/(1+y^2) = y
equating with gen. eq. x' + px = q
p = -1/(1+y^2), i.f = e^ int. of p = cot-1(x)
multiply by both side and integrate
dx/dy = (x + y^3 +y)/(1+y^2)
dx/dy = x/(1+y^2) + (y^3 +y)/(1+y^2)
dx/dy = x/(1+y^2) + y
dx/dy -x/(1+y^2) = y
equating with gen. eq. x' + px = q
p = -1/(1+y^2), i.f = e^ int. of p = cot-1(x)
multiply by both side and integrate
Similar questions