Question

One requires 0.01 moles of Na2co3.mass of na2co3.10h2o to be taken is

Answer 1

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Mass of Na₂CO₃.10H₂O = 46 + 12 + 48 + 180 = 286

1 mole contains 286 g of Na₂CO₃.10H₂O, so, 0.01 mole will contain:

0.01 x 286 = 2.86 g of Na₂CO₃.10H₂O must be taken

Answer 2

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