Question

One root of equation 7x2+kx-3=0 is 2/3,then find value of k

Answer 1

p(2/3)=14+k(2/3)-3
0 =14+k(2/3)-3
0-14+3=k(2/3)
-11 =k(2/3)
-11×3/2=k
-33/2=k
-16.5=k.

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Answer 2

put 2/3 in the eqn.

7× 4/9 + 2/3k -3=0
28/9 - 3 = - 2/3 k
1/9=-2/3k
k=-1/6.

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