Question

One root of px2-14x+8=0 is six times the other then p is

A)0 B)3
C)1/3 D)1


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Answer 1

Answer:

B)  3

Step-by-step explanation:

The quadratic equation Given = p$x^{2}$ + 14x + 8

Let  a and b be the roots of the equation:

b = 6a

Sum of roots = -b/a

Product of roots = c/a

Here a = p , b = -14 and c = 8

=> a+b = 14/p

=> ab = 8/p

=> a + 6a = 14/p

=> 7a = 14/p

=> a = 2/p

=> a * 6a = 8/p

=> 6$a^{2}$=8/p

=> 3$a^{2}$ = 4/p

=> 3 * (2/p$)^{2}$ = 4/p

=> 3*4/$p^{2}$=4/p

∴ p = 3