one root of quadratic eq. is 2xsquare+px-15=0 find p
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Answered by
4
Answer:
-5 is a root of quadratic equation 2x + px - 15 = 0
so, 2(-5)2 + p(-5) - 15 = 0
=> 50 - 5p - 15 = 0
=> 35 - 5p = 0
p = 7
now, put p = 7 in second quadratic equation,
p(x2 + x) + k = 0 => 7(x2 + x) + k = 0
=> 7x2 + 7x + k = 0
above equation has equal roots
so, D = b2 - 4ac = 0
=> 72 - 4 x 7 xk = 0
=> 7- 4k = 0
=> k = 7/4 = 1.75
hence, the value of k = 1.75
Answered by
5
Answer:
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