Question

one root of quadratic equation kx-10x+16=0 is four times the other , then find the value of k

Answer 1

Hey!!!....here is ur answer

given eq is.. kx^2-10x+16

let the roots are a and b

then.. a+b=10/k

here acc to question a=4b

and ab=16/k

now...

a+b=10/k

4b+b=10/k

5b=10/k

b=2/k

then..a=4b=8/k

putting the value of a and b in ab=16/k

8/k×2/k=16/k

16/k^2=16/k

1/k=1

k=1


Hope it will help you