Question

One root of the quadratic equation kx²-7x+12=0 is 3. find the value of k. *

4
1
--3​

Answer 1

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Answer 2

Answer:

Given quadratic equation: kx2−7x+12=0

If x=3 is the root of above equation, then k(3)2−7(3)+12=0

⇒9k−21+12=0

⇒k=1

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