Question

One's digit of a two digit number is 3times of the other if we interchange the digits and add the number to the orignal we get 88. What is the orignal number?

Answer 1

Let us assume x and y are the two digits of the two-digit number

Therefore, the two-digit number = 10x + y and the reversed number = 1oy + x

Given:

x = 3y --------1

Also given:

10y + x + 10x + y = 88

11x + 11y = 88

x + y = 8 -------------2

Substitute the value of x from eqn 1 in eqn 2

3y + y = 8

4y = 8

y = 2

Therefore, x = 3 * y = 3 * 2 = 6

Therefore, the two-digit number = 10x + y = (10*6) + 2 = 62