Question

One side of a rectangle is 21 cm longer than the other. The diagonal is
longer than bigger side by 6 cm. Find the area of the rectangle
​

Answer 1

Let shorter side be x cm

Longer side=(x+21)cm

Area=x(x+21)cm^2

Diagonal=(x+21+6)cm=(x+27)cm

Using PYTHAGORAS THEOREM,

(x+27)^2=(x+21)^2+x^2

x^2+729+54x=x^2+441+42x+x^2

729+54x=x^2+42x+441

x^2-12x-288=0

x^2-24x+12x-288=0

x(x-24)+12(x-24)=0

(x-24)(x+12)=0

x=-12,24

Side of a triangle is always positive so

x=24 only

Area=24(24+21)cm^2

=24*45cm^2

=1080 cm^2

Answer 2

Answer:

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