Question

divide the given polynomial by the given monomial
I.(5x^2-6x)÷3x​

Answer 1

Given :

Two expressions (5x²-6x) and 3x.

To Find :

The value of (5x²-6x)÷3x.

Answer:

Taking the given two expressions on Division.

=$\sf{\dfrac{6x^{2}-6x}{3x}}$

=$\sf{\dfrac{6x^{2}}{3x}-\dfrac{6x}{3x}}$

=$\sf{\dfrac{\cancel{6x^{2}}}{\cancel{3x}}-\dfrac{\cancel{6x}}{\cancel{3x}}}$

=${\underline{\boxed{\red{\sf{2x -2 }}}}}$

Answer 2

Given :-

• (5x² - 6x) ÷ 3x

Solution :-

$\implies\frac{5x {}^{2} - \: 6x}{3x}$

$\implies \frac{5x {}^{2} }{3x} \: - \: \frac{6x}{3x}$

$\implies \: \frac{5x }{3} - 2$

$\implies \: \frac{1}{3} (5x \: - \: 6)$