one side of a rectangle is 3ft shorter than twice the other side.Find the sides if the area is 209ft2.
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Answered by
3
and is 209ok it mauvhhbb
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22
Let the one side of rectangle be x ft
other side = 2x-3 ft
Equation
x(2x-3)= 209 ft^2
2x^2-3x-209=0
after factorising above equation we get
2x^2-22x+19x-209
(2x^2-22x) + (19x-209)
2x(x-11) +19(x-11)
(2x+19)(x-11)=0
2x+19=0
2x= -19
x= -19/2
x-11=0
x=11
the side can never be negative
so,
the first side=11ft
other side = 2×11-3=19 ft
other side = 2x-3 ft
Equation
x(2x-3)= 209 ft^2
2x^2-3x-209=0
after factorising above equation we get
2x^2-22x+19x-209
(2x^2-22x) + (19x-209)
2x(x-11) +19(x-11)
(2x+19)(x-11)=0
2x+19=0
2x= -19
x= -19/2
x-11=0
x=11
the side can never be negative
so,
the first side=11ft
other side = 2×11-3=19 ft
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