One side of a rhombus 10cms and one of its diagonals is 12cms the area of the rhombus
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Answered by
13
we know that rhombus all side equals
Than,
I hope it helps and plz mark brainliest
Than,
I hope it helps and plz mark brainliest
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harshitsinghunnnao:
please mark brainliest
Answered by
10
Solution:-
let, Rhombus ABCD.
given:-
•The sides of a rhombus are 10cm and one diagonal is 12 cm .
let, DO = OB = ? , BD = ?
and AO = OC = 6cm, and AC = 12 cm
1) we know diagonal of rhombus are equally bisect each other and they are perpendicular to each other.
2) All sides of rhombus are equal.
so,
by Pythagoras theorem.
=> (AB)² = ( AO )² + ( OB )²
=> (10)² = (6)² + (OB)²
=> 100 = 36 + (OB)²
=> 100 - 36 = (OB)²
=> 64 = (OB)²
i.e.
=> (OB)² = 64
=> OB = √64
=> OB = 8 cm
so, we know
DO = OB = 8 cm
hence, BD = 16 cm
Area of rhombus = [(AC)×(BD)]/2
Area of rhombus = [ 12 × 16 ]/2
Area of rhombus = [192]/2
Area of rhombus= 96 cm²
Hence length of diagonal rhombus
is 16 cm and area of rhombus is
96 cm².
i hope it helps you .
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