Question

one side of right angled triangle is 8 cm and difference between other two sides is 4 cm. find its area using heron's formula

Answer 1

Let the hypotenuse be 8 cms.

Acc. to question, the other two sides are x and x+4.

Using Pythagoras Theorem,

x^2 + (x-4)^2 = 64

Solve the equation, find the value of x. YOU WILL GET TWO VALUES OF x.

Eliminate the negative value.

Then find the sides and apply Herons Formula.




HOPE IT HELPS....

Answer 2

Step-by-step explanation:

using Pythagoras theorem

let hyp = x

side1 = x-4

side 2 = 8

..

x^2= (x-4)^2+64

x^2=x^2-8x+16+64

8x=16+64

8x=80

x=10 cms

--

side 1 = 8 cm.

side 2 = 10 cm.

side 3 = 10-4 cm.=6cm

..

area = sqrt(s(s-a)(s-b)(s-c))

s= 10+8+6 /2

s=24 /2

s= 12

..

Area = sqrt{12(12-8)(12-10)(12-6)

Area = sqrt{12(4)(2)(6)}

Area = sqrt{576}

Area = 24 sq. cm.