Question

One-sixth of the product of the 3 consecutive integers.

Answer 1

$let \: three \: consecutive \: numbers \: are \: x \: (x + 1) \: and \: (x + 2). \\ atq. \: ({x + (x + 1) + (x + 2)} )\times \frac{1}{6} \\ = (3x + 3) \times \frac{1}{6} \\ = 3(x + 1) \times \frac{1}{6} \\ = \frac{(x + 1)}{2}$