Math, asked by dustinlinus1997, 2 months ago

One tap can fill a cistern in 3 hours and the waste pipe empty the full tank in 5 hours.In what time the empty tank be full, if the tap and the waste pipe are kept open together​

Answers

Answered by sanjudnath
5

Answer:

One tap can fill a cistern in = 3 hours

Waste pipe can empty a cistern in = 5 hours

∴ One tap 1 hour work = 1/3

Waste pipe 1 hour work = 1/5

∴ One tap and waste pipe together 1 hour work

= 1/3 – 1/5 = (5 – 3)/15

= 2/15

∴ Empty cistern will be full in 15/2 hours

= 7. ½ hours

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