One tap fills a tank in 20 minutes and another tap fills it in 12 minutes. The tank being empty and if both taps are opened together, in how many Minutes the tank will be full?
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Time taken by first tap = 20 min
Hence in 1 min 1/20 of the work is done
Similarly in 1 min for tap 2 , 1/12 of the work will be done.
When both tanks are open together , then in one min 1/12 + 1/20 of the work is done.
Hence 1/15 of work is done in one min.
Hence total time taken is 15 min
So time taken to fill the bucket is 15 min when both taps are open.
Hence in 1 min 1/20 of the work is done
Similarly in 1 min for tap 2 , 1/12 of the work will be done.
When both tanks are open together , then in one min 1/12 + 1/20 of the work is done.
Hence 1/15 of work is done in one min.
Hence total time taken is 15 min
So time taken to fill the bucket is 15 min when both taps are open.
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1
I think in 16 minutes as only one tank should be filled . as both taps r turned on at a time half of the time of each taps should be calculated
if tap fills tank in 20 minutes it takes 10 minutes to fill half tank and if another tap fills the tank in 12 minutes it can fill half tank in 6 minutes
So if half half tanks fill in 10 and 6 minutes the whole tank will be filled in 16 minutes
if u feel this is right and useful mark it as brainliest answer
if tap fills tank in 20 minutes it takes 10 minutes to fill half tank and if another tap fills the tank in 12 minutes it can fill half tank in 6 minutes
So if half half tanks fill in 10 and 6 minutes the whole tank will be filled in 16 minutes
if u feel this is right and useful mark it as brainliest answer
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