Question

One third of a two digit number exceeds its one fourth by 7. what is the sum of digits of the number?

Answer 1

let the no. be x
(x/3)=(x/4)+7
calculate X,, and find sum of its digit.. it will be ans

Answer 2

The Sum of digits is 12

Given:

One third of a 2 digit number exceeds its one fourth by 7

To find:

The sum of the two digit number

Solution:

Consider the two digit number to be x.

One third of the number $=\frac{1}{3} x$

One fourth of the number $=\frac{1}{4} x$

$\frac{1}{3} x-\frac{1}{4} x=7$

$\frac{4 x-3 x}{12}=7$

$\frac{x}{12}=7$

$x=7 \times 12=84$

Hence, the 2 digit number is found to be 84

∴ The sum of digits of 84 = 8 + 4 = 12