One third of two digit number exceeds its one fourth by 7 what is the sum of digit of the number
Answers
Answered by
0
Step-by-step explanation:
Let the digit in the tens place be x and units place be y.
So, original number⇒10x+y
according to question,
1/3(10x+y)=1/4(10x+y)+7
10x+y=3{1/4(10x+y)+7}
10x+y=3/4(10x+y)+21
4(10x+y)=3(10x+y)+21
40x+40y=30x+30y+21
40x-30x+40y-30y=21
x+y=21
∴sum of the digit of the number is 21.
Answered by
2
Answer:
12
Step-by-step explanation:
let 2 digit number is x.
x/3= (x/4)+7
4x=3x+84
x=84
sum of its digit =8+4 =12
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