Question

One third of two digit number exceeds its one fourth by 7 what is the sum of digit of the number

Answer 1

Step-by-step explanation:

Let the digit in the tens place be x and units place be y.

    So, original number⇒10x+y

according to question,

1/3(10x+y)=1/4(10x+y)+7

10x+y=3{1/4(10x+y)+7}

10x+y=3/4(10x+y)+21

4(10x+y)=3(10x+y)+21

40x+40y=30x+30y+21

40x-30x+40y-30y=21

x+y=21

∴sum of the digit of the number is 21.

Answer 2

Answer:

12

Step-by-step explanation:

let 2 digit number is x.

x/3= (x/4)+7

4x=3x+84

x=84

sum of its digit =8+4 =12