one type of mixture contains 40% of alcohol and other contains 30% of alcohol with respect to its water. a cane is filled with 8 parts of the first mixture and 6 parts of the second mixture. find the percentage of alcohol in the new mixture. step by step explaination pls.
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Answer:
One type of liquid contains 25% of milk, the other contains 30% of milk. A container is filled with 6 parts of the first liquid and 4 parts of the second liquid. The percentage of milk in the mixture is
A) 27 %
B) 31 %
C) 29 %
D) 33 %
Correct Answer:
A) 27 %
Description for Correct answer:
According to question, milk in mixture
6×25100+4×30100=270100
For 10 parts = 270times10100 = 27%
Part of solved Mixture and Allegation questions and answers : >> Aptitude >> Mixture and Allegation
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