Math, asked by opkazuko, 2 months ago

one type of mixture contains 40% of alcohol and other contains 30% of alcohol with respect to its water. a cane is filled with 8 parts of the first mixture and 6 parts of the second mixture. find the percentage of alcohol in the new mixture. step by step explaination pls.​

Answers

Answered by riyaasati
0

Answer:

One type of liquid contains 25% of milk, the other contains 30% of milk. A container is filled with 6 parts of the first liquid and 4 parts of the second liquid. The percentage of milk in the mixture is

A) 27 %

B) 31 %

C) 29 %

D) 33 %

Correct Answer:

A) 27 %

Description for Correct answer:

According to question, milk in mixture

6×25100+4×30100=270100

For 10 parts = 270times10100 = 27%

Part of solved Mixture and Allegation questions and answers : >> Aptitude >> Mixture and Allegation

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