one year ago a father was 4 times as old as his son .in 6 years his age exceeds twice his son's age by 9 years .the ratio of their present ages is?
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one years ago fathers sge bex
his son's age be y
so acc to que
x-1=4(y-1)
x-1=4y-4
x-4y=-3 ....(1)
now
in 6 years fathers age be x+6
nd his sons age bey+6
acc ti que
x+6=2(y+6+9)
x+5=2y+30
x-2y=30-5
x-2y=25....(2)
by solving equation 1 nd 2 v get
y=14nd x=53
hope it helps u!!
his son's age be y
so acc to que
x-1=4(y-1)
x-1=4y-4
x-4y=-3 ....(1)
now
in 6 years fathers age be x+6
nd his sons age bey+6
acc ti que
x+6=2(y+6+9)
x+5=2y+30
x-2y=30-5
x-2y=25....(2)
by solving equation 1 nd 2 v get
y=14nd x=53
hope it helps u!!
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