Question

One year ago, a man was 8 times as old as
his son. Now his age is equal to the square of
his son's age. Find their present ages.​

Answer 1

Answer:

take the son's age as x.

man's age=8x

now

son's age=1+x

father's age = 8x+1

(1+x)2=8x+1

according to indentity,

(1)2+2×1×x+(x)2=8x+1

1+2x+x2=8x+1

transposing,

1-1+x2=-2x+8x

x2=6x

Answer 2

Answer:

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