Question

One year ago, a man was 8 times as old as his son. Now his age is equal to the square of his son’s age. Find their present ages. topic:Quadratic equation

Answer 1

Step-by-step explanation:

Let x be the age of the son one year ago, then the age of the man was 8x.

The present age of the son is (x+1) and that of the man is (8x+1). Then,

8x+1=(x+1)^2

8x+1=x^2+1+2x

x=0,6

As the age cannot be 0, so the value of x is 6.

So, present age of son =(x+1)=7 years

and Present age of man =(8x+1)=48 years

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