Question

One year ago, a man was 8 times as old as his son. Now his age is equal to the square of his son’s age. Find their present ages. topic: quadratic equation

Answer 1

Answer:

let the present age  of the son =x years.

it given that one years ago;a man 8 times as old as his son..

if x=1, then x²=1.

which is not possible as father's age cannot be equal to son's age.

so, x =7

hope it helpful for dear.................

Step-by-step explanation:

Answer 2

HEY MATE HERE'S YOUR ANSWER ⬇️

Let the present age of son be x so man's age is x².

A.T.Q{ 1 year ago}

8(x-1) = x²-1

8x-8 = x²-1

x²-8x+7=0

x²-7x-x+7=0

x(x-7)-1(x-7)=0

(x-1)(x-7)=0

x=1,7

[If present age will be 1 then man's age as 8 times of x-1 ie. 0 would be impossible so son's present age is 7 years & man's age is 49 years. This figure satisfies the equation as if we take the age of man and son 1 year ago; then man's age would be 8 times of the son ie. 6 and 48.]

Kindly follow me and thank my answers ❤