Question

The acceleration of a particle is a = (2+ + 1) m s 2
The particle is at rest at the origin initially. What
is the distance covered after 6 seconds ?
(A) 60 m
(B) 90 m
(C) 30 m
(D) 105 m.​

Answer 1

Explanation:

correct answer is A.

a=2(t−1)

=2t−2

dt

dv

=2t−2

dv=(2t−2)dt

integrating both side we get,

∫dv=∫(2t−2)dt

v=t

2

−2t+c

=(5)

2

−2×5

=25−10

=15m/s

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