Math, asked by geetv49011, 1 day ago

One year ago a man was 8 times older sa his son. Now his age is equal to the square of his sons age . Find the present age

Answers

Answered by K207
0

Answer:

Step-by-step explanation:

Let the present age of the son be x years. It is given that one year ago; a man was 8 times as old as his son. If x = 1, then x2 = 1, which is not possible as father's age cannot be equal to son's age. So, x = 7

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