Question

One year ago, a man was & times old as his.
son . Now his age is equal to the square of
eus son's age. Find their present rage.​

Answer 1

Please mention how many times. Write the question properly.

Answer 2

Let x be the age of the son one year ago, then the age of the man was 8x.

The present age of the son is (x+1) and that of the man is (8x+1). Then,

8x+1=(x+1) ^2

8x+1=x^2+1+2x

x=0,6

As the age cannot be 0, so the value of x is 6.

So, present age of son =(x+1)=7 years

and Present age of man =(8x+1)=48 years