Onit two urns contain 5 white 3 black and 2 white 3 black balls respectively one ball is drawn from each urn find the expected number of white ball drawn
Answers
41/40 is the expected number of white ball drawn
Step-by-step explanation:
1st urn contains 5 White 3 Black
2nd Urn contains 2 white 3 Black
White Ball drawn 0 => Both drawn balls are balck
Probability = (3/8) * (3/5) = 9/40
White Ball drawn 1 => White from 1st urn and black from 2nd urn or White from 2nd urn and black from 1st
= (5/8)(3/5) + (2/5)(3/8)
= 21/40
White Ball drawn 2 => Both white Balls are drawn
Probaility = (5/8)(2/8) = 10/40
Balls Drawn Probability
0 9/40
1 21/40
2 10/40
expected number of white ball drawn = 0 *(9/40) + 1 *(21/40) + 2*(10/40)
= 0 + 21/40 + 20/40
= 41/40
41/40 is the expected number of white ball drawn
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Answer:
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