Question

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Answer 1

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Answer 2

Answer:

Step-by-step explanation:

log₁₀x = a

it can be written as

10∧㏒₁₀x = 10ᵃ   (please note ∧ - power of )

=> x = 10ᵃ   (∵a∧㏒ₐx = x)

Now, 10²ᵃ⁻⁵  = 10²ᵃ / 10⁵

                    = (10ᵃ)² / 10⁵

                     = x²/10⁵.