Question

Only 27 question fast

Answer 1

Let the two cars be at points C and D. That is distance between the cars, CD = 100 m Let BD = d Hence BC = (100 – x) m Let the height of the balloon be AB = ‘h’ m In right ΔABD, θ = 45° In right ΔABC, θ = 60° ⇒ 100√3 – √3h = h ⇒ 100√3 = √3h + h = h(√3 + 1) ∴ h = 50√3(√3 + 1) m