Question

Only attempt if you Know
Two identical small equally charged conducting balls are suspended from long threads secured at one point. The charges and masses of the balls are such that they are in equilibrium when the distance between them is a (the length of the thread L >> a). One of the balls is then discharged. Again for the certain value of distance b (b << l) between the balls, the equilibrium is restored, the value of (a 3 /b 3 )=?

Answer 1

Answer:

hєчα mαtє ur αnѕ

ín thíѕ αttαchmєnt

plzz mαrk αѕ вrαnlíѕt

Answer 2

Explanation:

We know that

tanθ = kq² / mgx²

         x= distance b/w them

If the angle is to small , tanθ  = x/2l

         l =length of the string

Here tanθ = kq² / mga² = a/ 2l

              a³ = kq²2l /mg     -------1

Second case

When one of the ball is discharged ,the two balls meet together and collide.While touching , they share their charges

ie q/2 for each and gets separated by another distance which will be small say b

                b³ = kq²2l /4mg --------2

                     a³ / b³ = 4

                Hope you understand

This is Habel Sabu ......... Isn't it the Brainliest