Only for brainleist
Urgent pls
Attachments:
Answers
Answered by
1
U can solve like this.
Inner radius of hemispherical bowl = 5 cm
Thickness of the bowl = 0.25 cm
Outer radius (r) of hemispherical bowl = (5 + 0.25) cm
= 5.25 cm
Outer CSA of hemispherical bowl = 2πr2
= 2 * 22/7* (5.25)2
= 173.25 cm2
Inner radius of hemispherical bowl = 5 cm
Thickness of the bowl = 0.25 cm
Outer radius (r) of hemispherical bowl = (5 + 0.25) cm
= 5.25 cm
Outer CSA of hemispherical bowl = 2πr2
= 2 * 22/7* (5.25)2
= 173.25 cm2
Similar questions